Thermal Engineering
Conduction Heat Transfer Simulator
Analyze conduction heat transfer through a solid medium using Fourier's law of heat conduction. Adjust thermal conductivity, surface area, temperature differences, and material thickness to see how heat transfer rate is affected.
Governing Law
Fourier Conduction
1D Steady-State
Mesh
51 nodes
Linear Gradient
Output
CSV
Ready to export
Parameters
Material Preset
Temperature Sweep
Governing Equations (Conduction)
Fourier's Law
Q = (k * A * ΔT) / Δx
Heat Flux
q'' = Q / A = (k * ΔT) / Δx
Thermal Resistance
Rth = Δx / (k * A)
Temperature Gradient
dT/dx = -ΔT / Δx
Conductivity k = 205 W/mK (Aluminum).
Thermal resistance for this configuration is 0.00012 K/W.
The temperature drop across the thickness is completely linear under steady-state conditions with no internal heat generation.
Thermal Gradient and Heat Flux
Heat Transfer Rate (Q)
410000.0W
Rate in Kilowatts
410.000kW
Heat Flux (q'')
205000.0W/m²
Thermal Resistance (Rth)
0.00012K/W
Linear Temperature Gradient through Wall
Temperature Node Results
| Position x (m) | Depth (%) | Temperature (°C) |
|---|---|---|
| 0.000 m | 0% | 75.0°C |
| 0.005 m | 10% | 70.0°C |
| 0.010 m | 20% | 65.0°C |
| 0.015 m | 30% | 60.0°C |
| 0.020 m | 40% | 55.0°C |
| 0.025 m | 50% | 50.0°C |
| 0.030 m | 60% | 45.0°C |
| 0.035 m | 70% | 40.0°C |
| 0.040 m | 80% | 35.0°C |
| 0.045 m | 90% | 30.0°C |
| 0.050 m | 100% | 25.0°C |