Machine Design
Shaft Diameter Simulator
Analyze and determine the minimum safe diameter of rotating shafts subjected to combined bending and torsional loadings. Leverage the ASME B10.11 design formulas.
Code standard
ASME Code
Combined Load
Mesh
21 nodes
Torsional sweep
Output
CSV
Export ready
Parameters
Shaft Material
Animated torsion sweep
ASME Code Combined Stress
Equivalent Torque
T_e = \sqrt{(K_b \cdot M_b)^2 + (K_t \cdot M_t)^2}
Equivalent Bending Moment
M_e = \frac{1}{2} \left( K_b \cdot M_b + T_e \right)
Safe Shaft Diameter
d = \left( \frac{16 \cdot T_e}{\pi \cdot \tau_{allow}} \right)^{1/3}
Max Shear Stress
\tau_{max} = \frac{16 \cdot T_e}{\pi \cdot d^3}
Equivalent torque is calculated as 1250.0 N·m based on Kb = 1.5 and Kt = 1.0.
For a safe shear limit of 60 MPa, the minimum diameter is 47.34 mm.
Shaft Physical Deflection & Loadings
Required Diameter
47.34mm
Equivalent Torque (Te)
1250.0N·m
Eq. Bending (Me)
1000.0N·m
Max Shear Stress
60.0MPa
Required Diameter vs. Applied Torsion
Torsional Load Step Analysis
| Torsion Moment Mt (N·m) | Equivalent Torque Te (N·m) | Required Shaft Dia (mm) |
|---|---|---|
| 0 | 750.0 | 39.93 |
| 500 | 901.4 | 42.45 |
| 1000 | 1250.0 | 47.34 |
| 1500 | 1677.1 | 52.21 |
| 2000 | 2136.0 | 56.60 |
| 2500 | 2610.1 | 60.51 |
| 3000 | 3092.3 | 64.03 |
| 3500 | 3579.5 | 67.23 |
| 4000 | 4069.7 | 70.17 |
| 4500 | 4562.1 | 72.89 |
| 5000 | 5055.9 | 75.43 |